(12x^2(x^-3)^-4)/6x^5

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Solution for (12x^2(x^-3)^-4)/6x^5 equation: 


D( x )

x = 0

x^-3 = 0

x = 0

x = 0

x^-3 = 0

x^-3 = 0

1*x^-3 = 0 // : 1

x^-3 = 0

x należy do O

x in (-oo:0) U (0:+oo)

x^5*((12*x^2*(x^-3)^-4)/6) = 0

2*x^19 = 0 // : 2

x^19 = 0

x = 0

x in { 0} 

x belongs to the empty set

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